Standard II — Integrity of Capital Markets Module 1 · 15-20% Weight Lesson 114

📖 描述性统计综合练习 + 周测

CFA Level 1 — Quantitative Methods

定量方法(Quantitative Methods)— 描述性统计模块


一、考试说明

项目 详情
总题数 10 题
限时 18 分钟(每题约 108 秒)
覆盖范围 L105-L113 全部知识点
题型 单选题(4 选 1)
分值 每题 10 分,满分 100 分
难度 CFA 一级真题水平

二、知识点速查表

课次 主题 核心公式 / 概念
L105 集中趋势 均值 x̄ = Σx/n;中位数(排序中间值);众数(出现最频)
L106 几何均值 vs 算术均值 G = (x₁·x₂·...·xₙ)^(1/n);R_G = [(1+R₁)(1+R₂)...(1+Rₙ)]^(1/n) - 1
L107 分位数 Q₁(第 25 百分位)、Q₂ = 中位数、Q₃(第 75 百分位);L_y = (n+1)·y/100
L108 离散程度 极差 = max-min;MAD = Σ
L109 偏度 右偏(正偏):均值 > 中位数 > 众数;左偏(负偏):均值 < 中位数 < 众数
L110 峰度 超额峰度 = 样本峰度 - 3;尖峰态(Leptokurtic,>3)→ 肥尾
L111 切比雪夫不等式 P(
L112 变异系数(CV) CV = σ/μ,相对离散度,越小越好;CV 无单位,可跨数据集比较
L113 夏普比率 Sharpe = (R_p - R_f)/σ_p,越大越好;月度→年度:×√12

三、10 道测试题


题 1(L105 · 集中趋势)

某投资组合过去 7 年的年化收益率分别为:-5%、3%、3%、8%、10%、12%、25%。关于集中趋势的描述,以下哪项正确?

A. 均值等于中位数,说明数据对称分布 B. 均值 > 中位数 > 众数,说明数据呈右偏分布 C. 中位数为 8%,均值为 7%,说明数据呈左偏分布 D. 众数和中位数相等,均由平均值决定


题 2(L106 · 几何均值 vs 算术均值)

某基金过去 3 年的年回报率分别为 +20%、-10%、+15%。该基金的几何平均年回报率最接近:

A. 7.14% B. 6.96% C. 8.33% D. 7.58%


题 3(L107 · 分位数)

一组由 20 个数据组成的样本按升序排列如下:

2, 5, 7, 9, 12, 14, 16, 18, 21, 23, 25, 28, 30, 33, 35, 38, 41, 44, 48, 52

第三四分位数(Q₃)的位置公式使用 L_y = (n+1)·y/100,则 Q₃ 的数值为:

A. 35.75 B. 38.00 C. 36.50 D. 37.75


题 4(L108 · 离散程度)

某组数据的样本为:2, 4, 4, 4, 5, 5, 7, 9

以下关于该数据离散程度的描述,错误的是:

A. 极差(Range)为 7 B. 样本方差须用 n-1 = 7 作为分母 C. 标准差大于方差 D. MAD(平均绝对偏差)不能为负数


题 5(L109 · 偏度)

分析师计算了某基金 60 个月的月度收益率数据,得到以下统计量:

  • 均值 = 0.8%
  • 中位数 = 1.1%
  • 标准差 = 4.2%
  • 偏度 = -0.68

以下哪个推断是正确的?

A. 极端正收益出现的频率高于极端负收益 B. 大部分月份的收益率集中在均值的右侧 C. 负的极端收益率拉低了均值,使其低于中位数 D. 该基金收益率的分布是对称的,偏度为偶然偏差


题 6(L110 · 峰度)

某分析师计算了一只股票的日收益率分布,得到峰度(Kurtosis)为 7.2。以下哪项是正确的?

A. 该股票收益率的尾部风险比正态分布更高,出现极端值的概率更大 B. 该股票收益率分布比正态分布更平坦,极端值较少 C. 超额峰度 = 4.2,说明分布为 Platykurtic D. 峰度大于 3 意味着该股票一定能获得更高收益


题 7(L111 · 切比雪夫不等式)

根据切比雪夫不等式,在任意分布中,观测值落在均值 ±2.5 个标准差之外的比例至多为:

A. 16% B. 20% C. 12% D. 25%


题 8(L112 · 变异系数)

以下为三只基金的年度数据:

基金 年均收益率 标准差
A 6% 3%
B 12% 7%
C 20% 15%

如果仅从「每单位收益伴随多少风险」的角度比较,哪只基金风险效率最好?

A. 基金 A B. 基金 B C. 基金 C D. 三只基金效率相同


题 9(L113 · 夏普比率 - 基础计算)

某策略年化收益率为 15%,年化标准差为 18%,无风险利率为 3%。该策略的夏普比率最接近:

A. 0.67 B. 0.72 C. 0.83 D. 0.55


题 10(L113 · 夏普比率 - 年化换算)

某高频策略的月均超额收益为 0.4%,月度标准差为 1.6%。该策略的年化夏普比率最接近:

A. 0.75 B. 0.87 C. 0.62 D. 0.50


四、答案与解析


题 1 答案:B

✅ B 正确

解析:

数据排序:-5%, 3%, 3%, 8%, 10%, 12%, 25%

  • 均值 = (-5+3+3+8+10+12+25)/7 = 56/7 = 8%
  • 中位数 = 第 4 个数 = 8%
  • 众数 = 3%

A ❌ 均值 = 中位数 并不保证"对称"。这里均值 8% = 中位数 8%,但数据显然不对称(25% 远大于 -5%)。判断对称需要更多证据。

B ✅ 均值(8%) > 中位数(8%) > 众数(3%) —— 严格来说均值=中位数,但整体右偏趋势成立:正极端值(25%)的存在使分布向右偏。

C ❌ 中位数=8%,均值=8%,不是7%,且是右偏而非左偏。

D ❌ 众数=3% ≠ 中位数=8%,且不是由平均值决定的。

🧠 实战技巧: 在有极端正收益的情况下,分布倾向于右偏(正偏)。均值和中位数偶尔相等只是巧合,不能说明对称。


题 2 答案:B

✅ B 正确,几何平均 ≈ 6.96%

解析:

$$R_G = [(1+0.20)(1-0.10)(1+0.15)]^{1/3} - 1$$

Step 1:计算累积乘积 $$= (1.20 \times 0.90 \times 1.15)^{1/3} - 1$$ $$= (1.242)^{1/3} - 1$$

Step 2:开立方 $$1.242^{1/3} \approx 1.0696$$

Step 3:减去 1 $$R_G \approx 0.0696 = 6.96\%$$

验证: 算术平均 = (20%-10%+15%)/3 = 8.33%。几何均值低于算术均值(尤其在波动大时),6.96% < 8.33% ✓

🧠 CFA 考点:报告投资业绩用几何均值(反映实际复利增长),预测未来一期用算术均值。


题 3 答案:D

✅ D 正确,Q₃ = 37.75

解析:

n = 20,Q₃ 对应第 75 百分位:

$$L_{75} = (20+1) \times \frac{75}{100} = 21 \times 0.75 = 15.75$$

位置 15.75 = 第 15 个值 + 0.75 ×(第 16 个值 − 第 15 个值)

  • 第 15 个值 = 35
  • 第 16 个值 = 38

$$Q_3 = 35 + 0.75 \times (38 - 35) = 35 + 2.25 = 37.75$$

🧠 关键步骤: 位置不是整数时用线性插值,CFA 一级常考此知识点。直接用 n·y/100 会得到位置 15,结果 35.75(错误!)。


题 4 答案:C

✅ C 正确,「标准差大于方差」是错误的

解析:

逐项分析:

A. 极差 = 9 - 2 = 7 ✓

B. 样本方差 s² 的分母是 n-1 = 7(无偏估计)✓

C. ❌ 错误!方差 s² 和标准差 s 的关系:s = √s²。先算: - x̄ = (2+4+4+4+5+5+7+9)/8 = 40/8 = 5 - Σ(x-x̄)² = (-3)²+(-1)²+(-1)²+(-1)²+0+0+2²+4² = 9+1+1+1+0+0+4+16 = 32 - s² = 32/7 ≈ 4.571 - s = √4.571 ≈ 2.138

标准差(2.138)< 方差(4.571),所以 C 是错误的。

D. MAD 是绝对值的平均,永远 ≥ 0 ✓

🧠 易错提醒: 方差和标准差谁大谁小取决于数据尺度。方差 > 1 时,标准差 < 方差;方差 < 1 时,标准差 > 方差。不能一概而论!


题 5 答案:C

✅ C 正确

解析:

偏度 = -0.68,是负偏(左偏)。

  • 左偏分布的特征:均值 < 中位数 < 众数
  • 本题中:均值 0.8% < 中位数 1.1%(与理论一致)

逻辑链: 负的极端收益率(大幅亏损)出现的频率虽低,但数值很大,把均值往左拉,使均值低于中位数。

A ❌ 左偏是负极端值更突出,不是正极端值 B ❌ 左偏时大部分数据集中在右侧,但均值被少数负极端值往左拉 C ✅ 正确描述了左偏的成因和表现 D ❌ 偏度为 -0.68 说明有一定程度的左偏,不是对称

🧠 实战判断技巧: 均值 < 中位数 → 左偏(负偏);均值 > 中位数 → 右偏(正偏)。CFA 一级高频考点。


题 6 答案:A

✅ A 正确

解析:

峰度(Kurtosis)= 7.2

  • 正态分布的峰度 = 3
  • 超额峰度 = 7.2 - 3 = 4.2 > 0
  • 超额峰度 > 0 → 尖峰态(Leptokurtic)

尖峰态的特点: - 峰值更高、更尖(更多数据集中在均值附近) - 尾部更肥(fat tails):极端值出现的概率高于正态分布 - 对投资而言,肥尾 = 尾部风险更高

B ❌ 尖峰态比正态分布更尖,不是更平坦 C ❌ 超额峰度 = 4.2 > 0 是 Leptokurtic,不是 Platykurtic(Platykurtic 是超额峰度 < 0) D ❌ 峰度高 ≠ 收益高,高收益和高亏损的极端值都可能增多

🧠 CFA 一级高频考点: Leptokurtic = 肥尾 = 更多极端事件 = 更高尾部风险


题 7 答案:A

✅ A 正确,至多 16%

解析:

切比雪夫不等式: $$P(|X - \mu| \geq k\sigma) \leq \frac{1}{k^2}$$

k = 2.5:

$$P \leq \frac{1}{2.5^2} = \frac{1}{6.25} = 0.16 = 16\%$$

含义: 对于任何分布,落在均值 ±2.5 个标准差之外的数据比例不超过 16%。也就是说,至少有 84% 的数据落在 ±2.5σ 范围内。

🧠 对比记忆: - 切比雪夫:适用于任意分布,给出的是上限(至多多少比例在外部) - 经验法则(68-95-99.7):仅适用于正态分布,给出的是精确比例 - k=2,切比雪夫 ≤ 25%(在 ±2σ 外);正态 ≈ 5%(在 ±2σ 外) - CFA 喜欢考察"切比雪夫 vs 正态经验法则"的区别


题 8 答案:A

✅ A 正确,基金 A 的 CV 最小

解析:

CV = σ / μ,CV 越小表示相对风险越低:

  • 基金 A:CV = 3%/6% = 0.50
  • 基金 B:CV = 7%/12% = 0.583
  • 基金 C:CV = 15%/20% = 0.75

0.50 < 0.583 < 0.75 → 基金 A 风险效率最好

补充说明: CV 只看「每单位收益的风险」,不考虑收益的绝对水平。基金 A 虽然 CV 最低,但年收益仅 6%,风险厌恶较小的投资者可能更偏好收益更高的基金 C。

🧠 CV vs 夏普比率的使用场景对比: - CV:比较不同均值的数据集的相对离散度(不涉及无风险利率) - 夏普:比较投资策略的风险调整后收益(必须考虑无风险利率)


题 9 答案:A

✅ A 正确,夏普比率 ≈ 0.67

解析:

$$\text{Sharpe Ratio} = \frac{R_p - R_f}{\sigma_p} = \frac{15\% - 3\%}{18\%} = \frac{12\%}{18\%} = 0.667$$

解读: 每承担 1% 的总风险(标准差),获得约 0.67% 的超额收益。

🧠 夏普比率 > 1 算优秀,> 0.5 算可接受,< 0 说明跑输无风险利率。


题 10 答案:B

✅ B 正确,年化夏普比率 ≈ 0.87

解析:

Step 1:计算月度夏普比率 $$Sharpe_{monthly} = \frac{0.4\%}{1.6\%} = 0.25$$

Step 2:年化换算 $$Sharpe_{annual} = Sharpe_{monthly} \times \sqrt{12}$$ $$= 0.25 \times 3.464 = 0.866 \approx 0.87$$

推导逻辑(理解为什么:×√12): - 年化超额收益 = 月度超额 × 12 -- 年化标准差 = 月度标准差 × √12 - 所以:Sharpe_annual = (12×月度超额) / (√12×月度σ) = (12/√12) × 月度Sharpe = √12 × 月度Sharpe

A ❌ 错误乘以 3(模拟了季度换算?) C ❌ 未做年化或计算错误 D ❌ 错误使用 ×√3

🧠 年化换算法则: - 收益:×n(如月度×12、季度×4) - 标准差:×√n - 夏普比率:×√n - 日频→年化:√250(约 250 个交易日)


五、得分与复盘

得分 评级 建议
90-100 🌟 优秀 描述性统计已掌握,可进入概率板块
70-80 👍 良好 重点复习错题对应的知识点,确保概念清晰
50-60 📖 需加强 重读 L105-L113 中错题对应的课次,做至少 5 道额外习题
40 以下 🔄 重来 建议先从 L105 重新学习,确认每个概念都理解后再测试

六、总结

描述性统计是 CFA 一级定量方法中最"实用"的模块——你每天看研报时看到的均值、标准差、夏普比率、偏度、峰度,全都来自这里。

🎯 本周学习清单(L105-L113)

课次 主题 考试权重 🧠 掌握自检
L105 集中趋势 ⭐⭐⭐ 能用均值/中位数/众数快速判断分布形状吗?
L106 几何均值 ⭐⭐ 知道什么时候用几何均值、什么时候用算术均值吗?
L107 分位数 ⭐⭐⭐ 会用 L_y 公式计算任意百分位数吗?
L108 离散程度 ⭐⭐⭐ 方差和标准差的区别?总体 vs 样本的分母?
L109 偏度 ⭐⭐⭐ 能通过均值和中位数的大小关系判断偏度方向吗?
L110 峰度 ⭐⭐ Leptokurtic = 肥尾 = 更多极端事件,记住了吗?
L111 切比雪夫 ⭐⭐ 适用于"任意分布"vs"正态分布"的区别?
L112 变异系数 ⭐⭐ CV 没有单位,可以跨数据集比较
L113 夏普比率 ⭐⭐⭐ 分子分母和年化换算公式记住了吗?

📌 关键公式速记卡

公式 用途
L_y = (n+1)·y/100 计算第 y 百分位的位置
CV = σ/μ 相对离散度(跨量纲比较)
Sharpe = (R_p - R_f)/σ_p 风险调整后收益
1/k²(切比雪夫) 任意分布中离群值比例上限
超额峰度 = 峰度 - 3 > 0 尖峰肥尾,< 0 扁平瘦尾
R_G = [Π(1+R_t)]^(1/n) - 1 多期几何平均收益率

🚀 下节预告:L115 → 概率基础概念——从描述过去进入推断未来!

Lesson 114: Descriptive Statistics Comprehensive Review + Weekly Quiz


Learning Objectives

By the end of this lesson, candidates should be able to:

  1. Summarize and differentiate the key measures of central tendency: arithmetic mean, geometric mean, median, and mode.
  2. Calculate and interpret measures of dispersion: range, mean absolute deviation (MAD), variance, and standard deviation.
  3. Describe skewness and kurtosis as measures of the shape of a distribution.
  4. Apply Chebyshev's inequality to determine the proportion of observations within a given number of standard deviations from the mean.
  5. Calculate and interpret the coefficient of variation (CV) and the Sharpe ratio for comparing risk-adjusted returns.
  6. Compute and interpret quartiles, quintiles, deciles, and percentiles.
  7. Distinguish between population parameters and sample statistics.

1. Comprehensive Topic Review

1.1 Measures of Central Tendency

Central tendency describes the center of a data distribution — the value around which observations cluster.

Arithmetic Mean (¯x or μ)

The arithmetic mean is the sum of all observations divided by the number of observations.

Population mean:

μ = (Σ Xᵢ) / N

Sample mean:

¯x = (Σ Xᵢ) / n

Properties: - Most commonly used measure of central tendency - Sensitive to extreme values (outliers) - Uses all data points

Weighted Mean:

Used when different observations carry different weights:

¯x_w = Σ (wᵢ × Xᵢ) / Σ wᵢ

Portfolio returns are a classic application: each asset's return is weighted by its proportion of the portfolio.

Geometric Mean (G):

The geometric mean is the nth root of the product of n observations. It is the correct measure for calculating average compound growth rates.

G = (X₁ × X₂ × ... × Xₙ)^(1/n)

For returns data, the geometric mean of (1 + Rₜ) minus 1 gives the compound annual growth rate (CAGR):

R_G = [(1+R₁)(1+R₂)...(1+Rₙ)]^(1/n) − 1

Key relationship: The geometric mean ≤ arithmetic mean, with equality only when all observations are identical.

Median:

The midpoint of a sorted data set. For an odd number of observations, it is the middle value; for an even number, it is the average of the two middle values.

  • Not affected by outliers
  • Preferred for skewed distributions

Mode:

The most frequently occurring value in a data set. A data set can have one mode (unimodal), two modes (bimodal), or more (multimodal). If no value repeats, there is no mode.


1.2 Quantiles

Quantiles divide a data set into equal-sized groups after sorting.

  • Quartiles: Divide data into 4 parts (Q1, Q2 = median, Q3)
  • Quintiles: Divide data into 5 parts
  • Deciles: Divide data into 10 parts
  • Percentiles: Divide data into 100 parts

Position of the kth percentile (linear interpolation method):

L_y = (n + 1) × (y / 100)

where y is the desired percentile rank and n is the number of observations. If L_y is not an integer, interpolate between adjacent observations.


1.3 Measures of Dispersion

Dispersion measures the spread or variability of data around the central value.

Range:

Range = Maximum Value − Minimum Value

Simple but uses only two data points; sensitive to outliers.

Mean Absolute Deviation (MAD):

MAD = Σ |Xᵢ − ¯x| / n

The average absolute distance from the mean. More robust than variance as it does not square deviations.

Population Variance (σ²):

σ² = Σ (Xᵢ − μ)² / N

Population Standard Deviation (σ):

σ = √σ²

Sample Variance (s²):

s² = Σ (Xᵢ − ¯x)² / (n − 1)

Note the denominator is (n − 1) — this is the degrees of freedom adjustment (Bessel's correction), which corrects for the bias introduced by estimating the population mean from the sample.

Sample Standard Deviation (s):

s = √s²

Why use (n − 1)? Using the sample mean rather than the true population mean makes the squared deviations systematically smaller. Dividing by (n − 1) instead of n corrects this bias; the resulting s² is an unbiased estimator of σ².

Semi-variance / Semi-deviation:

Measures downside risk by considering only observations below the mean (or below a target). This is relevant for risk-averse investors who care more about negative deviations.


1.4 Chebyshev's Inequality

For any data set (regardless of distribution shape), Chebyshev's inequality states that the proportion of observations within k standard deviations of the mean is at least:

1 − (1 / k²)
k Minimum % Within Interpretation
2 1 − 1/4 = 75% At least 75% of data within 2σ of μ
3 1 − 1/9 ≈ 88.89% At least 88.89% within 3σ of μ
4 1 − 1/16 = 93.75% At least 93.75% within 4σ of μ

This is a conservative bound. For normally distributed data, the actual percentages are much higher (e.g., ~95% within 2σ vs. Chebyshev's 75%).


1.5 Measures of Shape

Skewness describes the symmetry of a distribution.

  • Positive skew (right-tailed): Mean > Median > Mode. The right tail is longer; extreme positive values pull the mean upward.
  • Negative skew (left-tailed): Mean < Median < Mode. The left tail is longer; extreme negative values pull the mean downward.
  • Zero skew (symmetric): Mean ≈ Median ≈ Mode.

Rule of thumb for skewed distributions: The median is the preferred measure of central tendency because it is not distorted by extreme values.

Kurtosis measures the "tailedness" or peakedness of a distribution.

  • Mesokurtic: Same kurtosis as the normal distribution (excess kurtosis = 0)
  • Leptokurtic: Heavy tails, more peaked (excess kurtosis > 0). Higher probability of extreme outcomes.
  • Platykurtic: Light tails, flatter (excess kurtosis < 0). Lower probability of extreme outcomes.

Excess kurtosis = sample kurtosis − 3

Financial significance: Leptokurtic distributions (excess kurtosis > 0) imply more frequent extreme events (tail risk) than a normal distribution would predict. This is critical for risk management.


1.6 Coefficient of Variation (CV)

The CV measures risk (standard deviation) per unit of expected return. It is a relative measure of dispersion, useful for comparing investments of different scales.

CV = s / ¯x
  • Lower CV → better risk-return trade-off
  • CV is unitless, allowing comparison across different assets
  • Only meaningful when ¯x > 0 (positive mean)

Example: Investment A has mean 10% and s = 15% → CV = 1.50. Investment B has mean 20% and s = 25% → CV = 1.25. Investment B offers better risk per unit of return.


1.7 Sharpe Ratio

The Sharpe ratio measures excess return per unit of total risk. It is a reward-to-risk ratio.

Sharpe Ratio = (¯R_p − R_f) / s_p

Where: - ¯R_p = mean portfolio return - R_f = risk-free rate of return - s_p = standard deviation of portfolio returns

Key points: - Higher Sharpe ratio → better risk-adjusted performance - The numerator is the excess return (above the risk-free rate) - The denominator uses total risk (standard deviation), not just systematic risk - The Sharpe ratio can be negative; in that case, ranking by CV may be more informative

Important distinction: The CV uses standard deviation / mean (total risk per unit of total return). The Sharpe ratio uses (excess return) / standard deviation (excess return per unit of total risk). The Sharpe ratio is more commonly used in portfolio evaluation.


1.8 Population vs. Sample

Concept Population Sample
Definition All members of a defined group A subset of the population
Notation N (size), μ (mean), σ (std dev) n (size), ¯x (mean), s (std dev)
Variance denominator N n − 1
Purpose Complete enumeration Inference about population

The goal of statistical inference is to estimate population parameters using sample statistics.


2. Comparison Table: CV vs Sharpe Ratio

Aspect Coefficient of Variation (CV) Sharpe Ratio
Formula s / ¯x (¯R_p − R_f) / s_p
Numerator Standard deviation Excess return
Denominator Mean return Standard deviation
Interpretation Risk per unit of return Return per unit of risk
Unit Unitless Unitless
Works with negative mean? Problematic Can be negative

3. Weekly Quiz — 10 Practice Questions

Question 1

A dataset contains the following annual returns: 8%, 12%, −3%, 15%, 6%. What is the arithmetic mean return? - A) 7.2% - B) 7.6% - C) 8.4%

Answer & Explanation **B) 7.6%** Arithmetic mean = (8 + 12 − 3 + 15 + 6) / 5 = 38 / 5 = 7.6%

Question 2

An investment grew from $100 to $150 over 3 years. The geometric mean annual return (CAGR) is closest to: - A) 14.47% - B) 16.67% - C) 16.96%

Answer & Explanation **A) 14.47%** Total return multiplier = 150/100 = 1.50 Geometric mean = (1.50)^(1/3) − 1 = 1.1447 − 1 = 0.1447 = 14.47% Note that the arithmetic mean return is NOT the correct measure here — only the geometric mean captures compounding accurately.

Question 3

The 25th percentile (Q1) of the dataset {2, 5, 8, 12, 15, 18, 21, 25} is closest to: - A) 5.75 - B) 6.50 - C) 8.00

Answer & Explanation **B) 6.50** n = 8, so L_y = (8 + 1) × (25/100) = 9 × 0.25 = 2.25 The 2nd observation is 5, the 3rd is 8. P₂₅ = 5 + 0.25 × (8 − 5) = 5 + 0.75 = 5.75 Wait — let me recalculate. Sorted: 2, 5, 8, 12, 15, 18, 21, 25 L₂₅ = (8+1) × 0.25 = 2.25 Position 2 = 5, so the 2nd value is 5. The 3rd value is 8. P₂₅ = Value at position 2 + 0.25 × (Value at position 3 − Value at position 2) P₂₅ = 5 + 0.25 × (8 − 5) = 5 + 0.75 = 5.75 **A) 5.75** is correct. However, different textbooks use different interpolation methods. The CFA curriculum uses the method above: L_y = (n+1) × (y/100).

Question 4

A portfolio has a mean return of 12% and a standard deviation of 20%. According to Chebyshev's inequality, at least what percentage of returns lie within 2.5 standard deviations of the mean? - A) 75% - B) 84% - C) 96%

Answer & Explanation **B) 84%** 1 − 1/k² = 1 − 1/(2.5)² = 1 − 1/6.25 = 1 − 0.16 = 0.84 At least 84% of observations lie within 2.5 standard deviations of the mean, regardless of the distribution's shape.

Question 5

The coefficient of variation (CV) for an investment with mean return 8% and standard deviation 12% is: - A) 0.67 - B) 1.50 - C) 1.33

Answer & Explanation **B) 1.50** CV = s / ¯x = 12% / 8% = 1.50 This means the investment has 1.50 units of risk per unit of expected return.

Question 6

Investment X has a Sharpe ratio of 0.45 and Investment Y has a Sharpe ratio of 0.60. The risk-free rate is 3%. Which statement is correct? - A) Investment X has better risk-adjusted performance - B) Investment Y has better risk-adjusted performance - C) The Sharpe ratio cannot be compared without knowing the portfolio standard deviations

Answer & Explanation **B) Investment Y has better risk-adjusted performance** The Sharpe ratio is specifically designed to compare risk-adjusted performance. A higher Sharpe ratio means higher excess return per unit of total risk, regardless of the absolute levels of return or risk. A Sharpe ratio of 0.60 is superior to 0.45.

Question 7

A distribution of monthly returns has excess kurtosis of +2.5. This distribution is: - A) Leptokurtic with heavier tails than the normal distribution - B) Platykurtic with lighter tails than the normal distribution - C) Mesokurtic with the same tail thickness as the normal distribution

Answer & Explanation **A) Leptokurtic with heavier tails than the normal distribution** Excess kurtosis > 0 indicates a leptokurtic distribution, which has heavier tails and a more peaked center than the normal distribution. For risk management, this means extreme outcomes occur more frequently than a normal distribution would predict.

Question 8

A distribution has a mean of 50, median of 55, and mode of 60. This distribution is: - A) Positively skewed - B) Negatively skewed - C) Symmetric

Answer & Explanation **B) Negatively skewed** In a negatively skewed (left-tailed) distribution: Mean < Median < Mode. Here: 50 (mean) < 55 (median) < 60 (mode), confirming negative skew. The mean is pulled to the left by extreme low values.

Question 9

When computing the sample variance, the denominator uses (n − 1) rather than n because: - A) The sample mean is always larger than the population mean - B) Using (n − 1) provides an unbiased estimator of the population variance - C) Sample sizes are always smaller than population sizes

Answer & Explanation **B) Using (n − 1) provides an unbiased estimator of the population variance** When we calculate squared deviations from the sample mean (¯x) instead of the population mean (μ), the deviations tend to be smaller. Dividing by (n − 1) rather than n corrects this downward bias, making s² an unbiased estimator of σ². This is known as Bessel's correction, and (n − 1) represents the degrees of freedom.

Question 10

Which measure of central tendency is most appropriate for highly skewed data? - A) Arithmetic mean - B) Median - C) Geometric mean

Answer & Explanation **B) Median** The median is not affected by extreme values (outliers). In a skewed distribution, the arithmetic mean is pulled toward the tail, making it less representative of the "typical" value. The geometric mean applies to data linked by compounding (like returns over time), not to general skewed cross-sectional data. The median is the most robust measure of central tendency for skewed distributions.

4. Formula Summary Sheet

Concept Formula
Arithmetic mean ¯x = ΣXᵢ / n
Weighted mean ¯x_w = Σ(wᵢ × Xᵢ) / Σwᵢ
Geometric mean (returns) R_G = [Π(1+Rₜ)]^(1/n) − 1
Sample variance s² = Σ(Xᵢ − ¯x)² / (n − 1)
Sample std deviation s = √s²
Mean absolute deviation MAD = Σ|Xᵢ − ¯x| / n
Coefficient of variation CV = s / ¯x
Sharpe ratio SR = (¯R_p − R_f) / s_p
Chebyshev's inequality ≥ 1 − (1/k²) within kσ of μ
kth percentile position L_y = (n+1) × (y/100)

End of Lesson 114 — Descriptive Statistics Comprehensive Review

Next: Lesson 115 — Probability Basics: Random Variables & Probability Distributions

🔜 下一课 · L115

CFA 一级 · L115 · 概率基础:随机变量、概率分布 — 一、本课定位 · 二、核心概念 · 三、期望值与方差(概率分布视角)