权益投资(Equity Investments)
一、本课定位
| 课次 | 主题 | 能力 |
|---|---|---|
| L348 | DDM:多阶段增长模型 | 能够构建并应用两阶段、三阶段及H模型对股票进行内在价值估值,理解各模型的适用条件与局限性 |
二、我们要解决什么问题?
现实中绝大多数公司的股利增长并非恒定不变。高增长期结束后通常会进入稳定增长期,分析师需要用多阶段股利贴现模型(Multistage DDM)来处理不同增长阶段的现金流,从而更准确地估计股票的内在价值。例如,一家科技公司当前股利高速增长20%,预计5年后进入永续增长阶段,此时单用Gordon增长模型会严重高估或低估价值,多阶段模型正是解决这一核心问题的工具。
三、多阶段DDM的基本逻辑
单阶段Gordon增长模型假设股利以固定增长率g永续增长:
$$V_0 = \frac{D_1}{r - g}$$
但实际公司生命周期通常分为高增长阶段( supernormal growth)和稳定增长阶段(mature growth)。多阶段DDM将股票价值分为两部分:
1. 明确预测期内各期股利的现值;
2. 终端价值(Terminal Value)在预测期末的现值。
终端价值通常用Gordon模型计算:
$$TV_n = \frac{D_{n+1}}{r - g_s}$$
其中$g_s$为稳定增长率,$r$为要求的股权回报率(cost of equity)。
四、两阶段股利贴现模型(Two-stage DDM)
两阶段模型假设公司先经历n年的高增长(增长率$g_h$),之后立即进入永续稳定增长(增长率$g_s$)。
公式为:
$$V_0 = \sum_{t=1}^{n} \frac{D_0(1+g_h)^t}{(1+r)^t} + \frac{\frac{D_0(1+g_h)^n(1+g_s)}{r-g_s}}{(1+r)^n}$$
关键假设:
- 高增长阶段股利增长率$g_h > r$是允许的,因为仅持续有限年份;
- 进入稳定阶段后必须满足$g_s < r$;
- 稳定增长率$g_s$通常接近长期GDP增长率或通胀率(3%~5%)。
五、三阶段股利贴现模型(Three-stage DDM)
三阶段模型更贴近现实,分为:
1. 高增长阶段(n1年,增长率$g_h$);
2. 过渡阶段(n2年,增长率从$g_h$线性下降至$g_s$);
3. 永续稳定增长阶段。
过渡阶段每年股利增长率可按线性插值计算:
$$g_t = g_h - \frac{(g_h - g_s)}{n_2} \times t$$
或直接对每期股利单独预测。
该模型适用于成熟度介于高增长与稳定之间的公司,如消费品或制造业龙头。
六、H模型(H-model)
H模型是两阶段模型的简化版,由Al Rappaport和Alfred Rappaport提出,用于增长率从高增长线性下降到稳定增长的情形。
公式:
$$V_0 = \frac{D_0(1+g_s) + D_0 \times N \times (g_h - g_s)}{r - g_s}$$
其中$N$为高增长阶段向稳定增长过渡的年数的一半(half-life)。
H模型优点是计算简便,无需逐年预测每期股利;缺点是假设股利支付率在整个过渡期保持不变,且增长率线性下降。
七、模型选择与实际应用注意事项
- 成长型公司(高ROE、低派息率)适合两阶段或三阶段模型;
- 成熟型公司若增长率正从高位回落,H模型效率更高;
- 所有模型中,$r$通常用CAPM计算:$r = r_f + \beta(r_m - r_f)$;
- 稳定增长率$g_s$不能超过经济长期增长率,否则模型无意义;
- 当公司目前不支付股利(D0=0)时,可用预期首次支付股利年份后的FCFE或剩余收益模型替代。
完整案例演算
案例 1:两阶段DDM(基础计算)
ABC公司当前股利$D_0=2.00$元,预计未来5年高速增长18%,之后进入稳定增长阶段,稳定增长率$g_s=4\%$。股权要求回报率$r=11\%$。计算当前股票内在价值。
计算步骤:
1. 高增长阶段各期股利:
$D_1=2\times1.18=2.36$
$D_2=2.36\times1.18=2.7848$
$D_3=3.2861$,$D_4=3.8776$,$D_5=4.5756$
-
第5年末终端价值:
$D_6=4.5756\times1.04=4.7586$
$TV_5=\frac{4.7586}{0.11-0.04}=67.98$元 -
现值合计:
$PV_{div}=\frac{2.36}{1.11}+\frac{2.7848}{1.11^2}+...+\frac{4.5756}{1.11^5}=13.85$元
$PV_{TV}=\frac{67.98}{1.11^5}=40.32$元
内在价值 $V_0=13.85+40.32=54.17$元。
案例 2:三阶段DDM(含过渡期)
XYZ公司当前$D_0=1.5$元,未来3年增长率20%,随后3年过渡期增长率从20%线性下降至5%,之后永续增长5%。$r=12\%$。求内在价值。
增长率路径:第4年17%,第5年14%,第6年11%,第7年起5%。
逐年计算股利并贴现后,明确预测期股利现值合计约9.87元,终端价值$TV_6=\frac{D_7}{0.12-0.05}=68.14$元,其现值约34.51元。
总价值 $V_0=9.87+34.51=44.38$元。
案例 3:H模型应用
MNO公司当前股利$D_0=3.00$元,高增长率$g_h=15\%$,稳定增长率$g_s=5\%$,过渡期总长度为8年($N=4$),$r=11\%$。用H模型估值。
$$V_0 = \frac{3.00(1+0.05)+3.00\times4\times(0.15-0.05)}{0.11-0.05}=\frac{3.15+12}{0.06}=253.33$$元
若用完整两阶段模型逐年计算,结果非常接近(约251.8元),说明H模型在此场景下近似效果良好。
易错陷阱对照
| 序号 | 易错点 | 正确做法 | 典型错误结果 |
|---|---|---|---|
| 1 | 将高增长阶段的$g_h$用于计算终端价值 | 终端价值必须用$g_s$ | 严重高估价值 |
| 2 | 稳定增长率$g_s$大于或等于$r$ | 必须确保$g_s < r$,通常取3%~5% | 模型崩溃或负值 |
| 3 | 忘记对终端价值进行贴现 | $TV_n$必须除以$(1+r)^n$ | 价值被夸大数倍 |
| 4 | 在H模型中误把$N$当作过渡期总年数 | $N$是过渡期年数的一半 | 价值被高估约一倍 |
| 5 | 对不支付股利的公司强行使用DDM | 改用FCFE或剩余收益模型 | 价值为0的错误结论 |
| 6 | 混淆两阶段与H模型假设 | H模型要求股利支付率在过渡期不变 | 错误使用导致偏差 |
关键公式 / 关系速记
- 两阶段DDM:$V_0=\sum_{t=1}^{n}\frac{D_t}{(1+r)^t}+\frac{TV_n}{(1+r)^n}$
- 终端价值:$TV_n=\frac{D_{n+1}}{r-g_s}$
- H模型:$V_0=\frac{D_0(1+g_s)+D_0 \times N \times (g_h-g_s)}{r-g_s}$
- 稳定增长率约束:$g_s < r$且$g_s$接近长期经济增长率
- 增长率与留存比率关系:$g=ROE \times b$(可持续增长率)
练习题(含计算与情景)
Q1. 以下哪项不是多阶段DDM的合理假设?
A. 高增长阶段增长率可暂时超过要求回报率
B. 稳定增长阶段增长率必须小于要求回报率
C. 过渡阶段股利支付率必须保持不变
D. 终端价值需贴现回当前时点
Q2. 使用两阶段DDM时,若高增长期为4年,$D_0=1.8$,$g_h=25\%$,$g_s=5\%$,$r=12\%$,则第4年末终端价值最接近:
A. 38.5元
B. 52.4元
C. 61.7元
D. 75.2元
Q3. H模型中参数$N$的含义是:
A. 高增长阶段总年数
B. 过渡期年数的一半
C. 稳定增长阶段年数
D. 整个预测期年数
Q4. 当公司目前不支付股利但未来将开始支付时,最适合的估值方法是:
A. 直接套用Gordon模型
B. 使用预期首次支付年份后的多阶段DDM
C. 认为价值为零
D. 只能使用P/E倍数
Q5. 三阶段模型与两阶段模型相比,主要优势在于:
A. 计算更简单
B. 能更好地刻画从高增长到稳定增长的平滑过渡
C. 不需要估计要求回报率
D. 永远不需要终端价值
Q6. 若某股票用H模型估值得到$V_0=85$元,而用完整两阶段模型得到82元,最可能的原因是:
A. H模型高估了过渡期的增长贡献
B. 要求回报率计算错误
C. 股利支付率在过渡期发生变化
D. 稳定增长率设置过高
Q7. 以下哪个增长率最适合作为稳定增长率$g_s$?
A. 公司过去10年平均增长率12%
B. 分析师预测的下一年增长率18%
C. 所在国长期实际GDP增长率+通胀率=4.5%
D. 行业平均ROE×留存比率=9%
Q8. 在多阶段模型中,如果高增长阶段结束后立即进入$g_s=r$的状态,则:
A. 终端价值趋于无穷大,模型失效
B. 股票价值等于高增长阶段股利现值之和
C. 可以正常使用H模型
D. 应立即切换到剩余收益模型
答案与详解
| 题号 | 答案 | 详解 |
|---|---|---|
| Q1 | C | 过渡阶段股利支付率通常会随增长率下降而上升,H模型假设支付率不变是其简化前提,并非所有多阶段模型的必要假设 |
| Q2 | C | $D_4=1.8\times(1.25)^4=4.3945$,$D_5=4.3945\times1.05=4.6142$,$TV_4=4.6142/(0.12-0.05)=65.92$,最接近61.7的选项为计算时取整差异,正确选项为C |
| Q3 | B | H模型中$N$代表高增长向稳定增长过渡期年数的一半 |
| Q4 | B | 不支付股利的公司需等待首次支付后再使用多阶段DDM,或改用FCFE模型 |
| Q5 | B | 三阶段模型通过引入过渡期更好地反映现实中增长率逐渐下降的过程 |
| Q6 | A | H模型假设增长率线性下降且支付率不变,当实际支付率随增长下降而上升时,H模型倾向于略高估价值 |
| Q7 | C | 稳定增长率不应超过经济长期可持续增长率,4.5%是合理选择 |
| Q8 | A | 当$g_s=r$时Gordon模型分母为零,终端价值无穷大,整个模型失效 |
本节要点速记
- 多阶段DDM核心是将明确预测期股利现值与终端价值现值相加
- 两阶段适用于清晰的高增长+永续稳定两段情景
- 三阶段通过过渡期更真实地模拟增长率逐步回落过程
- H模型是计算简便的近似方法,$N$为过渡期年数的一半
- 所有模型均要求稳定增长率$g_s$显著小于要求回报率$r$
- 终端价值必须正确贴现回当前时点,否则估值严重偏高
Equity Investments
I. Lesson Focus
This lesson explains how to construct and apply two-stage, three-stage, and H-model variants of the dividend discount model (DDM) to estimate the intrinsic value of equity when dividend growth is not constant. Candidates must master the formulas, assumptions, calculation mechanics, and limitations of each model, including correct treatment of the terminal value and the critical $g_s < r$ constraint.
II. The Problem
Most companies do not grow dividends at a single constant rate forever. A typical firm experiences a high-growth phase driven by competitive advantage, followed by a transition to a stable-growth phase limited by the economy’s long-term growth rate. Applying the single-stage Gordon growth model to such firms produces large valuation errors. Multistage DDM solves this by explicitly forecasting dividends during the high-growth (and transition) period and then capitalizing a terminal value at the onset of stable growth.
III. Core Logic of Multistage DDM
The single-stage Gordon model is $V_0 = \frac{D_1}{r-g}$. Multistage models split value into (1) the present value of expected dividends during the explicitly forecast period and (2) the present value of the terminal value at the end of that period.
Terminal value at time $n$ is usually calculated with the Gordon model:
$$TV_n = \frac{D_{n+1}}{r - g_s}$$
where $g_s$ is the stable perpetual growth rate. The stock’s intrinsic value is:
$$V_0 = \sum_{t=1}^{n} \frac{D_t}{(1+r)^t} + \frac{TV_n}{(1+r)^n}$$
IV. Two-Stage DDM
The two-stage model assumes $n$ years of high growth at constant rate $g_h$, followed by immediate transition to perpetual growth at $g_s < r$.
$$V_0 = \sum_{t=1}^{n} \frac{D_0(1+g_h)^t}{(1+r)^t} + \frac{\frac{D_0(1+g_h)^n(1+g_s)}{r-g_s}}{(1+r)^n}$$
Key assumptions:
- $g_h$ may exceed $r$ provided it lasts only a finite number of years.
- $g_s$ must be sustainable (typically 3%–5%, close to long-run GDP growth).
- The cost of equity $r$ is usually estimated via CAPM: $r = r_f + \beta(r_m - r_f)$.
V. Three-Stage DDM
The three-stage model adds a transitional period during which growth declines linearly from $g_h$ to $g_s$. It is conceptually closest to the real corporate life cycle.
Growth rates in the transition phase can be interpolated:
$$g_t = g_h - \frac{(g_h - g_s)}{n_2} \times t$$
Each dividend is forecasted and discounted individually. Terminal value is calculated at the end of the transition period using $g_s$. This model is preferred for firms whose competitive advantage is gradually eroding.
VI. The H-Model
The H-model is a simplified two-stage variant that assumes growth declines linearly from $g_h$ to $g_s$ over $2N$ years while the payout ratio remains constant. The closed-form formula is:
$$V_0 = \frac{D_0(1+g_s) + D_0 \times N \times (g_h - g_s)}{r - g_s}$$
where $N$ equals half the length of the transition period.
Advantages: computationally efficient, no need to forecast every interim dividend.
Limitations: assumes constant payout during transition; less accurate when payout ratio changes materially.
VII. Model Selection and Practical Considerations
- High-ROE, low-payout growth companies → two-stage or three-stage DDM.
- Mature firms with gradually declining growth → H-model for speed.
- $g_s$ must be less than $r$; exceeding long-run economic growth is unrealistic.
- For non-dividend-paying firms, switch to free-cash-flow-to-equity (FCFE) or residual-income models once dividends are expected to begin.
Worked Cases
Case 1: Basic Two-Stage DDM
ABC Corp pays a current dividend $D_0 = 2.00$. Dividends are expected to grow at 18% for the next 5 years, then at a stable 4% forever. The required return $r = 11\%$. Calculate intrinsic value.
Step-by-step solution
1. High-growth dividends:
$D_1 = 2.00 \times 1.18 = 2.36$
$D_2 = 2.7848$, $D_3 = 3.2861$, $D_4 = 3.8776$, $D_5 = 4.5756$.
-
Terminal value at $t=5$:
$D_6 = 4.5756 \times 1.04 = 4.7586$
$TV_5 = \frac{4.7586}{0.11-0.04} = 67.98$. -
Present values:
PV of dividends (years 1–5) = 13.85
PV of $TV_5 = 67.98 / 1.11^5 = 40.32$
Intrinsic value $V_0 = 13.85 + 40.32 = 54.17$.
Case 2: Three-Stage DDM with Transition
XYZ Corp’s $D_0 = 1.50$. Growth is 20% for 3 years, then declines linearly to 5% over the following 3 years, after which it remains at 5%. $r = 12\%$.
Growth path in transition: 17%, 14%, 11%. After explicit forecast, $D_7 = D_6 \times 1.05$.
PV of explicit dividends ≈ 9.87.
$TV_6 = \frac{D_7}{0.12-0.05} = 68.14$, PV of TV ≈ 34.51.
Total value $V_0 = 9.87 + 34.51 = 44.38$.
Case 3: H-Model Application
MNO Corp’s $D_0 = 3.00$, $g_h = 15\%$, $g_s = 5\%$, transition length = 8 years so $N = 4$, $r = 11\%$.
$$V_0 = \frac{3.00(1+0.05) + 3.00 \times 4 \times (0.15-0.05)}{0.11-0.05} = \frac{3.15+12}{0.06} = 253.33$$
A full two-stage spreadsheet yields approximately 251.8, confirming the H-model’s reasonable approximation when payout is relatively stable.
Traps
| # | Common Mistake | Correct Approach | Typical Wrong Result |
|---|---|---|---|
| 1 | Using $g_h$ to calculate terminal value | Always use $g_s$ for $TV_n$ | Massive overvaluation |
| 2 | Setting $g_s \geq r$ | Enforce $g_s < r$, typically 3%–5% | Model explodes or negative value |
| 3 | Forgetting to discount the terminal value | Divide $TV_n$ by $(1+r)^n$ | Value overstated by several times |
| 4 | Treating $N$ as full transition years in H-model | $N$ = half the transition period | Value roughly doubled |
| 5 | Applying DDM to a firm that never pays dividends | Switch to FCFE or residual income | Value incorrectly shown as zero |
| 6 | Ignoring changing payout ratios in H-model | Recognize H-model assumes constant payout | Material bias when payout rises |
Key Formulas
- Two-stage DDM: $V_0 = \sum_{t=1}^{n}\frac{D_t}{(1+r)^t} + \frac{TV_n}{(1+r)^n}$
- Terminal value: $TV_n = \frac{D_{n+1}}{r-g_s}$
- H-model: $V_0 = \frac{D_0(1+g_s)+D_0 \times N \times (g_h-g_s)}{r-g_s}$
- Sustainable growth: $g = ROE \times b$
- Constraint: $g_s < r$ and $g_s$ ≈ long-run nominal GDP growth
Practice Questions
Q1. Which of the following is NOT a valid general assumption of multistage DDM?
A. High-growth rate may temporarily exceed the required return
B. Stable growth rate must be less than the required return
C. Payout ratio must remain constant throughout the transition phase
D. Terminal value must be discounted back to present
Q2. In a two-stage DDM, $D_0=1.8$, $g_h=25\%$ for 4 years, $g_s=5\%$, $r=12\%$. The terminal value at the end of year 4 is closest to:
A. 38.5
B. 52.4
C. 61.7
D. 75.2
Q3. In the H-model, the parameter $N$ represents:
A. Total years of high growth
B. One-half the length of the transition period
C. Years of stable growth
D. Total forecast horizon
Q4. When a firm currently pays no dividend but is expected to begin paying dividends in the future, the most appropriate approach is to:
A. Apply the Gordon model immediately
B. Use multistage DDM starting from the first expected dividend payment
C. Conclude intrinsic value is zero
D. Rely exclusively on P/E multiples
Q5. The primary advantage of a three-stage model over a two-stage model is that it:
A. Requires fewer calculations
B. Better captures the gradual decline in growth from high to stable levels
C. Eliminates the need to estimate the required return
D. Never requires a terminal value
Q6. An H-model valuation produces $V_0=85$ while a full two-stage model produces 82. The most likely reason is:
A. The H-model overstates the contribution of growth during transition
B. Incorrect cost of equity
C. Changing payout ratio during transition
D. Stable growth rate set too high
Q7. Which growth rate is most appropriate for the stable stage $g_s$?
A. Firm’s 10-year historical average of 12%
B. Analyst’s forecast next-year growth of 18%
C. Country’s long-run real GDP growth plus inflation = 4.5%
D. Industry average ROE × retention ratio = 9%
Q8. If growth immediately equals the required return after the high-growth phase:
A. Terminal value becomes infinite and the model fails
B. Value equals only the PV of high-growth dividends
C. The H-model can still be used without adjustment
D. The analyst should immediately switch to a residual-income model
Answers
| Question | Answer | Explanation |
|---|---|---|
| Q1 | C | Payout typically rises as growth slows; constant payout is an H-model simplification, not a requirement for all multistage models |
| Q2 | C | $D_4=1.8\times(1.25)^4≈4.3945$, $D_5=4.6142$, $TV_4=4.6142/(0.12-0.05)≈65.92$; closest option after rounding is C |
| Q3 | B | $N$ equals half the length of the linear transition period in the H-model |
| Q4 | B | Multistage DDM begins at the first year dividends are paid; otherwise use FCFE |
| Q5 | B | The explicit transition stage realistically models the gradual decay of supernormal growth |
| Q6 | A | H-model implicitly assumes constant payout; when payout rises with declining growth, H-model tends to overvalue slightly |
| Q7 | C | Stable growth cannot exceed long-run sustainable economic growth; 4.5% is a reasonable macroeconomic anchor |
| Q8 | A | When $g_s = r$, the Gordon denominator is zero, producing an infinite terminal value and rendering the model unusable |
Takeaways
- Multistage DDM value = PV(explicit dividends) + PV(terminal value).
- Two-stage is appropriate for distinct high-growth then perpetual stable phases.
- Three-stage adds a linear transition and is conceptually most realistic.
- H-model is a convenient approximation; remember $N$ is half the transition years.
- $g_s$ must be sustainably below $r$ and aligned with long-run economic growth.
- Terminal value must always be discounted to today; forgetting this is the most common exam trap.