Standard II — Integrity of Capital Markets Module 1 · 15-20% Weight Lesson 121

📖 标准正态分布与 Z 分数

CFA Level I · L121 · Standard Normal Distribution & Z-Scores

定量方法(Quantitative Methods)— 概率论模块 · 第七课


一、本课定位

L120 学了正态分布:钟形对称曲线,由 μ 和 σ 完全定义,68-95-99.7 经验法则快速估算概率。但经验法则只能给 μ±1σ、μ±2σ、μ±3σ 三个整数倍的结果。想精确知道 P(收益 > 2.3%),就需要标准正态分布和 z 分数。

项目 说明
模块 2.4 概率论
前置知识 L120 正态分布(μ、σ、68-95-99.7 规则)
后续衔接 L122 对数正态分布
难度 ★★★★☆
考试权重 高(z 表查值 + 计算,3-4 题)
阅读时间 约 15 分钟

二、核心概念

1. 为什么需要标准化?

正态分布 N(μ, σ²) 有无穷多种——不同的 μ,不同的 σ,生成无数条不同钟形曲线。为每种 (μ, σ) 组合都编一本概率表是不可能的。

解法:把所有正态分布转化到同一个"标尺"上。 就像把美元、欧元、日元全部换成同一种基准货币——z 分数就是"统一换算工具"。


2. 标准正态分布(Standard Normal Distribution)

$$\text{记作: } Z \sim N(0, 1)$$

$$f(z) = \frac{1}{\sqrt{2\pi}} \cdot e^{-\frac{z^2}{2}}$$

性质 标准正态
均值 μ 0
标准差 σ 1
68-95-99.7 68% 在 [-1,1];95% 在 [-2,2];99.7% 在 [-3,3]

🧠 标准正态分布只有一套 z 表——查一次,管天下。


3. Z 分数(Z-Score)

Z 分数的含义:"X 距离均值多少倍标准差?"

$$z = \frac{X - \mu}{\sigma}$$

符号 含义
X 原始数据点
μ 总体均值
σ 总体标准差
z 标准化值(偏离均值几个 σ)

案例 1:标准化计算

X ~ N(100, 25),即 μ = 100,σ = 5:

X 值 z = (X−100)/5 z 值 含义
110 (110−100)/5 +2.0 比均值高 2σ
92.5 (92.5−100)/5 −1.5 比均值低 1.5σ
100 (100−100)/5 0 正好在均值上

📊 标准化"抹去"了原始单位(元、%、点),只剩下无单位的 σ 倍数。


4. Z 表的四种查表场景(考试核心)

以下是精简 z 表(CFA 考试常用值):

z 0.00 0.05 0.10
0.0 0.5000 0.5199 0.5398
0.5 0.6915 0.7088 0.7257
1.0 0.8413 0.8531 0.8643
1.5 0.9332 0.9394 0.9452
1.96 0.9750 — —
2.0 0.9772 0.9798 0.9821
2.5 0.9938 0.9946 0.9953
3.0 0.9987 0.9989 0.9990

四种场景:

场景 公式 示例
① P(X ≤ a) 左尾 直接查 P(Z ≤ z) P(Z ≤ 1.2) = 0.8849
② P(X ≥ a) 右尾 1 − P(Z ≤ z) P(Z ≥ 1.2) = 1 − 0.8849 = 0.1151
③ P(a ≤ X ≤ b) 中间 F(b) − F(a) P(−1 ≤ Z ≤ 1) = 0.8413 − 0.1587 = 0.6826
④ 已知概率求临界值 反查 z 表 95% 双尾 → z = 1.96

负 z 处理——利用对称性:

$$P(Z \leq -z) = 1 - P(Z \leq z)$$


案例 2:实际金融问题

某基金月收益 ~ N(0.8%, 2.5%²)。求亏损超过 2% 的概率。

$$z = \frac{-2\% - 0.8\%}{2.5\%} = -1.12$$

P(Z ≤ −1.12) = 1 − P(Z ≤ 1.12) = 1 − 0.8686 = 0.1314 ≈ 13.14%

📊 该基金每月有约 13% 的概率亏损超过 2%。


5. 关键 z 值——务必背诵

z P(Z ≤ z) 应用
0 0.5000 均值点
1.00 0.8413 1σ 右侧
1.28 ≈0.90 90% 单尾
1.645 0.95 95% 单尾
1.96 0.975 95% 双尾
2.00 0.9772 2σ 右侧
2.33 ≈0.99 99% 单尾
2.58 0.995 99% 双尾
3.00 0.9987 3σ 右侧

🎯 口诀:「单尾 95→1.645,双尾 95→1.96,单尾 99→2.33,双尾 99→2.58」


6. 逆标准化:从概率反推 X

$$X = \mu + z \cdot \sigma$$

案例 3:VaR 逆向计算

投资组合日收益 ~ N(0.05%, 1.1%²)。95% 置信水平日 VaR:

  • 95% 置信 → P(Z ≤ z) = 0.05 → z = −1.645
  • VaR = 0.05% + (−1.645)(1.1%) = −1.76%

📊 95% 置信水平下,单日最大损失不超过 1.76%。


7. z 分数的金融应用矩阵

应用 z 分数角色
VaR 计算 z = (损失阈值 − μ)/σ
异常检测
跨资产比较 不同收益标准化后可比
信用评分 Altman Z-Score 破产预测
业绩归因 α/σ(α) > 1.96 → 统计显著

三、核心公式速记

公式 用途
z = (X − μ) / σ X 标准化为 z 分数
X = μ + z·σ z 反推原始 X
P(Z ≤ −z) = 1 − P(Z ≤ z) 负 z 用对称性查表
P(a ≤ X ≤ b) = F(z₂) − F(z₁) 区间概率
CI: μ ± z_{α/2}·σ 置信区间

四、常见陷阱

❌ 错误 ✅ 正确
忘记 X−μ 的正负号 X < μ 时 z 为负,必须用对称性
z 分数和原始 X 混淆 z = 2 是偏离 2σ,不是 X = 2
方差当标准差用 z 的分母是 σ,不是 σ²
区间概率用错 P(a ≤ X ≤ b) = F(b) − F(a),不是加
1.96 做单尾 1.96 是双尾 95%;单尾 95% 用 1.645
不画图直接查表 先画示意图确认要左尾/右尾/中间

五、实战测试

【测试题】

Q1(概念题) X ~ N(50, 25)。计算 z 分数时正确的做法是:

A. 计算 z = (X − 50) / 5,因为 σ = 5
B. 计算 z = (X − 50) / 25,因为 σ² = 25
C. 计算 z = X − 50 / 5,因为减法优先级高于除法
D. 不需要计算 z,直接用 X 查标准正态表


Q2(计算题) X ~ N(80, 144)。求 P(X > 95) 最接近的值:

A. 0.1056
B. 0.1250
C. 0.1587
D. 0.2112


Q3(计算题) X ~ N(200, 400)。若 P(X < k) = 0.8413,则 k 最接近: (已知 P(Z ≤ 1.00) = 0.8413)

A. 210
B. 220
C. 240
D. 260


Q4(综合题) 三只股票标准化收益(z 分数)计算中:

股票 收益 μ σ z 公式
A 5.2% 3.0% 1.5% (5.2−3.0)/1.5
B −1.8% 0.5% 0.8% (−1.8−0.5)/0.8
C 8.0% 4.0% 2.0% (8.0−4.0)/2.0

按 z 分数从大到小排列(最佳 → 最差):

A. C > A > B
B. A > C > B
C. C > B > A
D. A > B > C


Q5(进阶概念题) 关于 z 分数,哪一项错误?

A. z 分数衡量偏离均值的标准差倍数
B. 即使原始分布非正态,z 分数依然可计算
C. z > 0 说明 X 低于均值
D. 标准化后任何数据的样本均值和样本标准差变为 0 和 1


【答案与解析】

A1:A

  • A ✅ σ² = 25 ⇒ σ = 5,z = (X − 50)/5 正确
  • B ❌ z 的分母必须是标准差 σ = 5,不是方差 σ² = 25
  • C ❌ 先做减法再做除法,需要括号:(X − 50)/5
  • D ❌ 原始 X 不能直接用标准正态表,必须先标准化

A2:A — 0.1056

计算过程: - σ² = 144 ⇒ σ = 12 - z = (95 − 80) / 12 = 15/12 = 1.25 - P(Z ≤ 1.25) = 0.8944 - P(Z > 1.25) = 1 − 0.8944 = 0.1056

⚠️ 注意:先准确计算 z 值,区分左尾/右尾的转换。


A3:B — 220

  • σ² = 400 ⇒ σ = 20
  • P(Z ≤ 1.00) = 0.8413 ⇒ z = 1.00
  • k = μ + z·σ = 200 + 1.00 × 20 = 220

A4:B — A > C > B

逐只计算 z: - 股票 A:z_A = (5.2 − 3.0)/1.5 = 2.2/1.5 = 1.467 - 股票 B:z_B = (−1.8 − 0.5)/0.8 = −2.3/0.8 = −2.875 - 股票 C:z_C = (8.0 − 4.0)/2.0 = 4.0/2.0 = 2.000

排名:C(z=2.0) > A(z=1.47) > B(z=−2.88)?等等……

仔细看:z_C = 2.000,z_A = 1.467,顺序是 C > A > B。

🧠 等一下——按照这个计算,应该是 C > A > B,对应选项 A。

但发现问题出在这里: z_A = (5.2 − 3.0)/1.5 = 2.2/1.5 ≈ 1.467 z_C = (8.0 − 4.0)/2.0 = 4.0/2.0 = 2.000 z_B = (−1.8 − 0.5)/0.8 = −2.3/0.8 = −2.875

C(2.00) > A(1.47) > B(−2.88) → 选项 A:C > A > B

📊 z 分数不仅能排序,还能量化"好多少":C 比均值多 2σ,A 多 1.47σ,B 比均值少 2.88σ。


A5:C

  • A ✅ z 分数的定义就是"偏离均值的标准差的个数"
  • B ✅ z 分数只是数学变换:(X−μ)/σ,不需要正态分布假设
  • C ❌ z > 0 意味着 X 高于均值(分子 X−μ > 0)
  • D ✅ 标准化后样本均值变为 0,样本标准差变为 1(数学性质)

这道题容易选错 D,因为"任何数据"听起来太绝对。但标准化是纯数学操作——把数据减去均值除以标准差后,新数据的均值必然是 0,标准差必然是 1。这和分布形状无关。


📚 下一课 L122:对数正态分布——为什么资产价格用对数正态而不是正态建模

Quantitative Methods — Probability Module · Lesson 7


I. Lesson Positioning

L120 covered the normal distribution: a bell-shaped symmetric curve fully defined by μ and σ, with the 68-95-99.7 empirical rule for quick probability estimates. But that rule only gives you the three integer σ multiples. To precisely compute P(return > 2.3%), you need the standard normal distribution and z-scores.

Item Description
Module 2.4 Probability
Prerequisite L120 Normal Distribution (μ, σ, 68-95-99.7 rule)
Next L122 Log-normal Distribution
Difficulty ★★★★☆
Exam Weight High (z-table lookup + calculation, 3–4 questions)
Reading Time ~15 minutes

II. Core Concepts

1. Why Standardize?

The normal distribution N(μ, σ²) has infinitely many possibilities — different μ, different σ, generating countless different bell curves. Publishing a separate probability table for every (μ, σ) combination is impossible.

Solution: transform all normal distributions onto a single "ruler." Just as you'd convert USD, EUR, and JPY into a single base currency to compare them — the z-score is that "universal conversion tool."


2. Standard Normal Distribution

$$\text{Denoted: } Z \sim N(0, 1)$$

$$f(z) = \frac{1}{\sqrt{2\pi}} \cdot e^{-\frac{z^2}{2}}$$

Property Standard Normal
Mean μ 0
Std Dev σ 1
68-95-99.7 68% in [−1,1]; 95% in [−2,2]; 99.7% in [−3,3]

🧠 The standard normal has only one z-table — look it up once, use it everywhere.


3. Z-Score

The z-score answers: "How many standard deviations is X away from the mean?"

$$z = \frac{X - \mu}{\sigma}$$

Symbol Meaning
X Raw data point
μ Population mean
σ Population standard deviation
z Standardized value (# of σ away from μ)

Example 1: Standardization

X ~ N(100, 25), i.e., μ = 100, σ = 5:

X z = (X−100)/5 z-value Meaning
110 (110−100)/5 +2.0 2σ above mean
92.5 (92.5−100)/5 −1.5 1.5σ below mean
100 (100−100)/5 0 exactly at mean

📊 Standardization strips away the original units (%, dollars, points), leaving only unit-free σ multiples.


4. Four Z-Table Lookup Scenarios (Exam Core)

Abbreviated z-table (CFA exam common values):

z 0.00 0.05 0.10
0.0 0.5000 0.5199 0.5398
0.5 0.6915 0.7088 0.7257
1.0 0.8413 0.8531 0.8643
1.5 0.9332 0.9394 0.9452
1.96 0.9750 — —
2.0 0.9772 0.9798 0.9821
2.5 0.9938 0.9946 0.9953
3.0 0.9987 0.9989 0.9990

Four scenarios:

Scenario Formula Example
① P(X ≤ a) left tail Direct lookup P(Z ≤ z) P(Z ≤ 1.2) = 0.8849
② P(X ≥ a) right tail 1 − P(Z ≤ z) P(Z ≥ 1.2) = 1 − 0.8849 = 0.1151
③ P(a ≤ X ≤ b) middle F(b) − F(a) P(−1 ≤ Z ≤ 1) = 0.8413 − 0.1587 = 0.6826
④ Find cutoff from probability Reverse lookup 95% two-tailed → z = 1.96

Handling negative z — use symmetry:

$$P(Z \leq -z) = 1 - P(Z \leq z)$$


Example 2: Real Finance Problem

A fund's monthly return ~ N(0.8%, 2.5%²). Probability of a loss exceeding 2%:

$$z = \frac{-2\% - 0.8\%}{2.5\%} = -1.12$$

P(Z ≤ −1.12) = 1 − P(Z ≤ 1.12) = 1 − 0.8686 = 0.1314 ≈ 13.14%

📊 This fund has roughly a 13% chance of losing more than 2% in any given month.


5. Critical Z-Values — Must Memorize

z P(Z ≤ z) Application
0 0.5000 Mean point
1.00 0.8413 1σ to the right
1.28 ≈0.90 90% one-tailed
1.645 0.95 95% one-tailed
1.96 0.975 95% two-tailed
2.00 0.9772 2σ to the right
2.33 ≈0.99 99% one-tailed
2.58 0.995 99% two-tailed
3.00 0.9987 3σ to the right

🎯 Mnemonic: "One-tail 95 → 1.645, two-tail 95 → 1.96, one-tail 99 → 2.33, two-tail 99 → 2.58"


6. Reverse Standardization: From Probability Back to X

$$X = \mu + z \cdot \sigma$$

Example 3: VaR Calculation

Portfolio daily return ~ N(0.05%, 1.1%²). Daily VaR at 95% confidence:

  • 95% confidence → P(Z ≤ z) = 0.05 → z = −1.645
  • VaR = 0.05% + (−1.645)(1.1%) = −1.76%

📊 At 95% confidence, the max single-day loss is 1.76%.


7. Financial Applications of Z-Scores

Application Z-Score Role
VaR z = (loss threshold − μ) / σ
Anomaly Detection
Cross-asset Comparison Different returns become comparable after standardization
Credit Scoring Altman Z-Score for bankruptcy prediction
Performance Attribution α / σ(α) > 1.96 → statistically significant

III. Key Formulas

Formula Purpose
z = (X − μ) / σ Standardize X to a z-score
X = μ + z·σ Convert z back to original X
P(Z ≤ −z) = 1 − P(Z ≤ z) Negative z via symmetry
P(a ≤ X ≤ b) = F(z₂) − F(z₁) Interval probability
CI: μ ± z_{α/2}·σ Confidence interval

IV. Common Pitfalls

❌ Mistake ✅ Correct
Ignoring sign of X − μ When X < μ, z is negative — must use symmetry
Confusing z-score with raw X z = 2 means 2σ away, not X = 2
Using variance instead of std dev Denominator is σ, not σ²
Wrong operation for interval prob P(a ≤ X ≤ b) = F(b) − F(a), not addition
Using 1.96 for one-tailed test 1.96 is two-tailed 95%; use 1.645 for one-tailed
Looking up z-table without sketching Always draw a quick diagram to confirm left/right/middle

V. Practice Questions

【Questions】

Q1 (Concept) X ~ N(50, 25). When computing the z-score, the correct approach is:

A. Compute z = (X − 50) / 5, because σ = 5
B. Compute z = (X − 50) / 25, because σ² = 25
C. Compute z = X − 50 / 5, because subtraction takes priority over division
D. No z needed; look up X directly in the standard normal table


Q2 (Calculation) X ~ N(80, 144). The value of P(X > 95) is closest to:

A. 0.1056
B. 0.1250
C. 0.1587
D. 0.2112


Q3 (Calculation) X ~ N(200, 400). If P(X < k) = 0.8413, then k is closest to: (Given: P(Z ≤ 1.00) = 0.8413)

A. 210
B. 220
C. 240
D. 260


Q4 (Comprehensive) Standardized returns (z-scores) for three stocks:

Stock Return μ σ z Formula
A 5.2% 3.0% 1.5% (5.2−3.0)/1.5
B −1.8% 0.5% 0.8% (−1.8−0.5)/0.8
C 8.0% 4.0% 2.0% (8.0−4.0)/2.0

Rank by z-score from highest to lowest (best → worst performer):

A. C > A > B
B. A > C > B
C. C > B > A
D. A > B > C


Q5 (Advanced Concept) Which statement about z-scores is incorrect?

A. A z-score measures the number of standard deviations from the mean
B. Z-scores can be computed even when the underlying distribution is non-normal
C. z > 0 means X is below the mean
D. After standardization, any dataset's sample mean becomes 0 and sample standard deviation becomes 1


【Answers & Explanations】

A1: A

  • A ✅ σ² = 25 ⇒ σ = 5, so z = (X − 50)/5 is correct
  • B ❌ The denominator must be standard deviation σ = 5, not variance σ² = 25
  • C ❌ Subtraction first, then division — need parentheses: (X − 50)/5
  • D ❌ Raw X values cannot be used directly with the standard normal table — must standardize first

A2: A — 0.1056

Calculation: - σ² = 144 ⇒ σ = 12 - z = (95 − 80) / 12 = 15/12 = 1.25 - P(Z ≤ 1.25) = 0.8944 - P(Z > 1.25) = 1 − 0.8944 = 0.1056

⚠️ Note: Compute z accurately first, then distinguish between left-tail and right-tail conversions.


A3: B — 220

  • σ² = 400 ⇒ σ = 20
  • P(Z ≤ 1.00) = 0.8413 ⇒ z = 1.00
  • k = μ + z·σ = 200 + 1.00 × 20 = 220

A4: A — C > A > B

Compute each z-score: - Stock A: z_A = (5.2 − 3.0)/1.5 = 2.2/1.5 = 1.467 - Stock B: z_B = (−1.8 − 0.5)/0.8 = −2.3/0.8 = −2.875 - Stock C: z_C = (8.0 − 4.0)/2.0 = 4.0/2.0 = 2.000

Ranking: C (2.00) > A (1.47) > B (−2.88)

📊 Z-scores not only rank performance but quantify "how much better": C is 2σ above its mean, A is 1.47σ above, B is 2.88σ below.


A5: C

  • A ✅ Definition of z-score: number of standard deviations from the mean
  • B ✅ Z-score is purely a mathematical transformation: (X − μ)/σ, no normality assumption required
  • C ❌ z > 0 means X is above the mean (numerator X − μ > 0)
  • D ✅ After standardization, the sample mean always becomes 0 and sample standard deviation becomes 1 (mathematical property)

D may sound "too absolute," but it's a mathematical certainty: subtracting the mean makes the new mean 0, and dividing by σ makes the new standard deviation 1. This holds regardless of distribution shape.


📚 Next Lesson L122: Log-normal Distribution — why asset prices use log-normal instead of normal modeling

🔜 下一课 · L122

CFA 一级 · L122 · 对数正态分布 — 一、本课定位 · 二、核心概念 · 三、核心公式速记